# Line slope calculator 3x-5y=3

**Straight line given by points A[1; 0] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x-0.6

**Canonical form of the line equation:**3x-5y-3 = 0

**Parametric form of the line equation:**

x = 5t+1

y = 3t ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = -0.6

**Distance line from the origin:**d

_{0}= 0.5145

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[3.5; 1.5]

**Perpendicular Bisector equation:**5x+3y-22 = 0

**Vector OA = (1; 0) ; |OA| = 1**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**