# Line slope calculator 9x-8y=-8

**Straight line given by points A[0; 1] and B[8; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.125x+1

**Canonical form of the line equation:**9x-8y+8 = 0

**Parametric form of the line equation:**

x = 8t

y = 9t+1 ; t ∈ R

**Slope:**m = 1.125

**Slope angle of line: φ =**48°21'59″ = 0.8442 rad

**X intercept:**x

_{0}= -0.8889

**Y intercept:**y

_{0}= q = 1

**Distance line from the origin:**d

_{0}= 0.6644

**The length of the segment AB: |AB| =**12.0416

**Vector: AB =**(8; 9)

**Normal vector: n =**(9; -8)

**Midpoint of the segment AB: M =**[4; 5.5]

**Perpendicular Bisector equation:**8x+9y-81.5 = 0

**Vector OA = (0; 1) ; |OA| = 1**

**Vector OB = (8; 10) ; |OB| = 12.8062**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 38°39'35″ = 0.6747 rad**