# Line slope calculator 4x-y=28

**Straight line given by points A[7; 0] and B[8; 4]**

## Calculation:

**Slope-intercept form of line:**y = 4x-28

**Canonical form of the line equation:**4x-y-28 = 0

**Parametric form of the line equation:**

x = t+7

y = 4t ; t ∈ R

**Slope:**m = 4

**Slope angle of line: φ =**75°57'50″ = 1.3258 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = -28

**Distance line from the origin:**d

_{0}= 6.791

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; 4)

**Normal vector: n =**(4; -1)

**Midpoint of the segment AB: M =**[7.5; 2]

**Perpendicular Bisector equation:**x+4y-15.5 = 0

**Vector OA = (7; 0) ; |OA| = 7**

**Vector OB = (8; 4) ; |OB| = 8.9443**

**Scalar product OA .OB = 56**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**